Aball is thrown vertically upward. after t seconds, its height h (in feet) is given by the function h(t)= 96t-16t^2 . after how long will it reach its maximum height? do not round your answer. time: seconds

The time taken to reach the maximum height = 3 s

Quadratic function is a function that has the term x²

The quadratic function forms a parabolic curve

The general formula is

where a, b, and c are real numbers and a ≠ 0.

The parabolic curve can be opened up or down determined from the value of a. If a is positive, the parabolic curve opens up and has a minimum value. If a is negative, the parabolic curve opens down and has a maximum value

So the maximum is if a <0 and the minimum if a> 0.

After t seconds, a ball height h (in feet) is given by the function h (t) = 96t-16t²

The maximum value of the function is obtained if the first derivative of the function h (t) = 0

96-32t = 0

96 = 32t

t = 3 s

The maximum height

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the fencing

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domain of the function

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560

hope this : )