What is the equation of the line perpendicular to 5x − 2y = −18 that contains the point (10, 4)?

y=-2/5x
y=-2/5x+8
y=-5/2x+29
y=5/2x-29

To find the slope of the line perpendicular to 5x-2y=-18. I would suggest changing the equation to point slope form or y=(5x/2)+9. The slope of the line perpendicular is the negative reciprocal. To find the reciprocal flip the slope of 5/2 to 2/5 and add a negative sign to -2/5. Now to find the constant of the equation solve the point slope form of y-4=-2/5(x-10) this simlifies to y=-2/5x+8. Your answer is the y=-2/5x+8.

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