how can one thirdx − 2 = one fourthx + 11 be set up as a system of equations?

3y − x = −6
4y − x = 44

3y + x = −6
4y + x = 44

3y − 3x = −6
4y − 4x = 44

3y + 3x = −6
4y + 4x = 44

1/3x - 2 = 1/4x + 11it looks to me like one y was subbed in for another...

ur 2 equations are :
y = 1/3x - 2 and y = 1/4x + 11...but we need them in standard form...

y = 1/3x - 2
-1/3x + y = -2 ..multiply by 3
-x + 3y = -6or 3y - x = -6 <==

y = 1/4x + 11
-1/4x + y = 11 ...multiply by 4
-x + 4y = 44 or 4y - x = 44 <==