5pennies ,3 dimes and 4 quarters are placed in a bag .what is the probability of selecting a quarter and then another quarter, given the first coin is not returned to the back after it is drawn? a. 2/11 b. 1/11 c. 1/22 d. 5/33

5+3+4 = 12 total coins

4 are quarters so first selection = 4/12 reduces to 1/3

after taking a coin out there would be 11 coins left and 3 quarters left

 so 2nd selection would be 3/11

now multiply 3/11 x 1/3 = 3/33 which reduces to 1/11

B. 1/11 is the correct answer

the answer is a

step-by-step explanation:

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6