After 1 second, the ball is 121 feet in the air; after 2 seconds, it is 224 feet in the air. find the height, in feet, of the ball after 3 seconds in the air.

The height, in feet, of the ball after 3 seconds in the air = 309

Step-by-step explanation:

We have

After 1 second, the ball is 121 feet in the air

     Here s = 121 ft ,  t = 1 s

After 2 seconds, it is 224 feet in the air  

     Here s = 224 ft ,  t = 2 s  

Subtracting two equations

         2u-a-(u-a)=242-112

          u = 130 ft/s

          130 - a = 112

            a = 18 ft/s²

When t = 3s

The height, in feet, of the ball after 3 seconds in the air = 309

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)