Five times the sum of a number and 27 ig greater than or equal to six times the sum of that number and 26 . what is the solution set of this problem

Given

5(x + 27) ≥ 6(x + 26)

Find

The solution set of x

Solution

Eliminate parenthses.

... 5x + 135 ≥ 6x + 156

Subtract 5x+156

... -21 ≥ x

The solution set is all real numbers less than or equal to -21.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

i dont know men

step-by-step explanation: