Astudent performed the following steps to find the solution to the equation x^2-2x-8=0. where did the student go wrong?

step 1. factor the polynomial into (x-4) and (x-2)
step 2. x-4=0 and x-2=0
step 3. x=4 and x=3

a. the student did not make any mistakes, the solution is correct
b. in step 1
c. in step 2
d. in step 3

In step 1, because you want to find factors that multiply to -8 and add to -2. So the correct factorization is (x-4)(x+2). The student got the minus sign wrong.

(Then in step 3 the x=3 is also very wrong, but that looks more like a typo).
(Also, it should be x-4=0 OR x+2=0, there is no x for which both factors are 0 at the same time!)

There is no question, there is just the answer.