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Mathematics, 13.11.2019 08:31 Robinlynn228

The absolute value function g(x) = |x + 7| βˆ’ 4 is translated 5 units right and 2 units up to become gβ€²(x). the quadratic function f(x), graphed below, is also moved 5 units right and 2 units up to become fβ€²(x). which of these two transformed functions has a range of y ≀ βˆ’2 and what is the vertex of this transformed function?

gβ€²(x) has a range of y ≀ βˆ’2 and its vertex is at (βˆ’2, βˆ’2).
gβ€²(x) has a range of y ≀ βˆ’2 and its vertex is at (2, βˆ’2).
fβ€²(x) has a range of y ≀ βˆ’2 and its vertex is at (3, βˆ’2).
fβ€²(x) has a range of y ≀ βˆ’2 and its vertex is at (βˆ’7, βˆ’6).

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