Jeff invested $3000 in an account that earns 6.5% interest, compounded annually. the formula for compound interest is a=p(1+i)t .

how much did jeff have in the account after 3 years ?

a. $13,476.38
b. $3623.85
c. $3390.00
d. $9585.00

Option B - $3623.85

Step-by-step explanation:

Given : Jeff invested $3000 in an account that earns 6.5% interest, compounded annually. The formula for compound interest is  .

To find : How much did Jeff have in the account after 3 years ?

Solution :

The formula for compound interest is .

Where A is the amount

P is the principal = $3000

I is the interest = 6.5%=0.065

t is the time = 3 years

Substitute in the formula,

Therefore, Option B is correct.

The amount Jeff have in the account is $3623.85

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)