Show work! worth 40 !

from points a and b, the distance between in which is 1020 mi. two trains left simultaneously towards each other. the speed of one train was 10 mph greater than the speed of the other. in 5 hours the train had not met yet and were 170 mi apart. find the speed of both trains.

80 and 90 mph

Step-by-step explanation:

Given that A and B have a distance of 1029 miles between them.  Two trains each start from A and B and move towards each other.

Let the speed of I train be s

Then speed of second train = s+10 (since 10 greater than speed of I train)

Relative speed = s+s+10 = 2s+10

In 5 hours they travelled together a distance of 1020-170 =850 miles

Distance travelled = 850 miles

Relative speed = 2s+10

Time taken = 5 hours

Since distance = time x speed

we have

5(2s+10) =850

2s+10 =170

s = 80

Speed of the trains are 80mph and 90 mph

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

24

step-by-step explanation:

if it takes 8 pounds to make 12 divide 12 by 8 and you get 1.5, 1.5 x 16 = 24