If a child's knowledge of the alphabet is limited to the letters a, b, c, i, and e, and if the child writes two letters at random (assume the child may write the same letter twice), what is the probability that they are both vowels?

The formula for probability is # of favorable outcomes divided by the total number of outcomes. 

So we know that there are a total of 5 letters. The child writes two letters, so we will have x/5 * x/5. Now, it is asking, what is the probability that they are both vowels.

We can see that a, i, and e are vowels, so the probability if the child were to write one letter would be 3/5. Since he is writing 2, you can multiply 3/5 * 3/5, which would give you your answer, 9/25. Therefore the probability that both letters are vowels is 9/25.

Hope this helps! Please rate, leave a thanks, and mark a brainliest answer. (Not necessarily mine). Thanks, it really helps! :D