Atraining field is formed by joining a rectangle and two semicircles, as shown below. the rectangle is 89m long and 66m wide. find the area of the training field. use the value 3.14 for π , and do not round your answer. be sure to include the correct unit in your answer.

The area of the field will be given by:
Area=[area of the semi circle]+[area of rectangle]
Area of semicircle is given by:
Area=πr^2
where;
radius,r=66/2=33 m
thus;
Area=3.14*33^2
3,419.46 m^2

The area of the rectangle is given by:
Area=89*66
=5,874 m^2
Hence the area of the field will be:
A=(5,874)+(3,419.46)
A=9,293.46 m^2