Identify the horizontal asymptote of f(x) = 3 over 5 x.

Horizontal asymptote is y =0

Step-by-step explanation:

Given is a function as

with x in the denominator.

Obviously we can find the vertical asymptote by equating denominator to 0

i.e. x=0 or y axis is the vertical asymptote

To find horizontal asymptote:

Let us write x in terms of y and find any exception to y

From given function we can write

x=3/5y

Here x becomes undefined for y=0

so horizontal asymptote is y=0

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

the answer is c hope it

step-by-step explanation: