If ef = hg and hg = 16, find the diameter of k

Diameter of the circle K = 20 units

Step-by-step explanation:

Given that : EF = HG

Also, HG = 16 units

⇒ EF = 16 units

Now, any line drawn perpendicular to the chord always bisects the chord

⇒ KI will bisect the chord EF

⇒ EI = 8 units

Now, in ΔEIK using Pythagoras theorem we have :

⇒ EK² = 8² + 6²

⇒ EK² = 100

⇒ EK = 10 units

So, Radius of the circle K = 10 units

Now, Diameter of the circle K = 2 × 10

                                                  = 20 units

the answer is a

step-by-step explanation:

because if you put 1 in to the square root of x it equals 300.