Arectangular deck is 12ft by 14ft. when the length and width are increased by the same amount, the area becomes 288sq. ft. by how much were the dimensions increased?

Dimensions of rectangle = 12 + x and 14 + x

(12 + x) (14 + x) = 288

 x^2 + 26x + 168 = 288

 x^2 + 26x - 120 = 0

(x + 30) (x - 4) = 0

x=-30, x =4

 since 4 is positive

 the dimensions increased by 4 feet

check the answer

12+4 = 16

14 +4 = 18

18*16 =288

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

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step-by-step explanation: