Given that a=84, b=66 and a=13 solve triangle abc. round to the nearest hundredth.

In this item, we are asked to determine the sides and the angles of the given triangle ABC. We use the cosine law for the first one,

                           A/cos A = B/cos B

Substituting,
                       84 / cos 13° = 66/ cos b
The value of b is equal to 40°.

The sum of the measures of the angle in the triangle is equal to 180°
                               a + b + c = 180°
          
                              13 + 40 + c = 180°
     
                                     c = 127°

Use again Sine Law,
                           B/ sinb= C / sin c

Substituting,
                           66/sin 13 = C/sin  .
The value of c from the equation is  127.32. 

Is there a picture?