Henry's little brother has $8$ identical stickers and $4$ identical sheets of paper. how many ways are there for him to put all of the stickers on the sheets of paper, if only the number of stickers on each sheet matters?

The easiest way to visualize and answer this is to list all possible combinations or arrangements on the 4 sheets of paper.

Take note that the arrangement is as following:

# of stickers on sheet 1 - # of stickers on sheet 2 - # of stickers on sheet 3 - # of stickers on sheet 4

8 – 0 – 0 – 0

7 – 1 – 0 – 0

6 – 2 – 0 – 0

6 – 1 – 1 – 0

5 – 3 – 0 – 0

5 – 2 – 1 – 0

5 – 1 – 1 – 1

4 – 4 – 0 – 0

4 – 3 – 1 – 0

4 – 2 – 2 – 0

4 – 2 – 1 – 1

3 – 3 – 2 – 0

3 – 3 – 1 – 1

3 – 2 – 2 – 1

2 – 2 – 2 – 2

Therefore there are a total combinations of 15 arrangements of stickers on sheets of paper.

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

step-by-step explanation:

options