Which set of side lengths is a pythagorean triple?
2, 3, 13
5, 7, 12
10, 24, 29
11, 60, 61

Option (D) 11, 60, 61 is a Pythagorean triple.

Step-by-step explanation:

For each set of lengths we will check with Pythagorean theorem.

(A) 2, 3, 13

    2² + 3² = 4 + 9 ≠ 13²

So option (A) is not a Pythagorean triple.

(B)  5, 7, 12

     5² + 7² = 25 + 49

                 = 74 ≠ 12²

  So not the answer.

(C)  10, 24, 29

     10² + 24² = 100 + 576

                    = 676 ≠  29²

  So option is not the answer.

(D)  11, 60, 61

     11² + 60² = 121 + 3600

                   = 3721

                   = 61²

Therefore, 11, 60, 61 is the Pythagorean triplet.

Option (D) is the answer.

i dont know sorry

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°