If y varies directly as x, and y is 6 when x is 72, what is the value of y when x is 8?

Direct variation is of the for y=kx, where k is the constant of variation  (inverse variation is of the form y=k/x)

We are given a point, (72,6), so we can solve for k

y=kx

6=72k

1/12=k 

So our equation is:

y=x/12, so when x=8

y=8/12

y=2/3

Ihave, but this question is gonna probably get deleted.