What is the y-intercept of the graph of the function f(x)=x^2+3x+5?

The y-intercept of a function is where the line or curve crosses the y-axis. And since the y-axis isvalways at x=0, then when can plug 0 into the equation for all x's.
1) Start by replacing "f(x)" with "y"
f(x)=x^2+3x+5 --> y = x^2+3x+5
2) then plug 0 into all places for x
y = x^2+3x+5 --> y = 0^2 + 3•0 + 5
so y = 0 + 0 + 5 = 5
Our y-intercept is therefore at y = 5

X=y+4 is the answe

Anyone can me with these answers