Given that the two triangles are similar, solve for x if au = 20x + 108, ub = 273, bc = 703, uv = 444, av = 372 and ac = 589.

Data:

segment AU = 20x + 108,
segment UB = 273,
segment BC = 703,
segment UV = 444,
segment AV = 372 and
segment AC = 589.

From the figure:

1) Similarity => segment AB / segment BC = segment AU / segment UV

2) segment AB = segment AU + segment UB = 20x + 108 + 273 = 20x + 381

=> (20x + 381) / 703 = (20x + 108) / 444

=> 444 (20x + 381) = 703 (20x + 108)

=> 8880x + 169164 = 14060x + 75924

=> 14060x - 8880x = 169164 - 75924

=> 5180 x = 93240

=> x = 93240 / 5180

=> x = 18

x = 18

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