If the nth partial sum of the sequence an is given by
n
sigma 2k+4
k=1
then what is the nth term of the sequence?
a. 6
b. 2n+4
c. 6+8+10+12++(2n+4)
d. 2(1)+4+2(n)+4

This is an example of a series in arithmetic progression.

The nth term an can be calculated using the formula:

an = a1 + (n – 1) d

where: a1 = is the 1st term of the series

d = common difference

Calculating for the 1st term:

a1 = 2k + 4 = 2 (1) + 4 = 6

Calculating for the common difference by :

d = a2 – a1

d = 2 (2) + 4 – 6

d = 2

Therefore calculating for an:

an = 6 + (n – 1) 2

an = 6 + 2n -2

an = 2n + 4

Therefore the answer is B. 2n+4

typically if you want , you would actually put questions here for us to you. but hey, that's just me. maybe someone will magically answer the questions for you without knowing what they are.

answer: 1, 3 and 5 are correct

step-by-step explanation: