Determine the solution set of (x - 4)^2 = 12.

{4 + 2√3, 4 - 2√3}
{4 - 2√3, 4 - 2√3}
{2√3 + 4, 2√3 - 4}

x = 4 + 2 sqrt(3) or x = 4 - 2 sqrt(3) thus {4 + 2√3, 4 - 2√3} is your answer!

Step-by-step explanation:

Solve for x over the real numbers:

(x - 4)^2 = 12

Take the square root of both sides:

x - 4 = 2 sqrt(3) or x - 4 = -2 sqrt(3)

Add 4 to both sides:

x = 4 + 2 sqrt(3) or x - 4 = -2 sqrt(3)

Add 4 to both sides:

x = 4 + 2 sqrt(3) or x = 4 - 2 sqrt(3)

the reason why your question keeps getting deleted because this is not a school related question : )

i will answer your question though.

i never tried church's