The length of rectangular field is 7 m less than 4 times the width. the perimeter is 136 m. find the width and length

15 m and 53 m.

Step-by-step explanation:

Let the length of the rectangular field = x m

and width = y m

From the statement "Length is 7m less than 4 times the width"

x = 4y - 7 (1)

"perimeter of the field is 136 m."

2 (x + y) = 136

x + y = 68 (2)

Now we replace the value of x from equation 1 to 2

4y - 7 + y = 68

5y - 7 = 68

5y = 68 + 7 = 75

y = 15 m

From equation (2)

x + 15 = 68

x = 68 - 15

  = 53 m

Therefore, length and width of the field are 15 m and 53 m.

answer: the answer to your question is parallel

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !