What is x2+7x+12=0 in standard form

Not sure what standard form is, but I can solve for x
so I'm assuming that x2 means x squared or x^2 so

x^2+7x+12=0
since it equals zero, if we can factor it, then
if we have xy=0 then x and/or y=0 so

to factor x^2+7x+12
find what 2 numbers multiply to get 12 and add to get 7 so
12=2 times 2 times 3 or 2 times 6 or 1 times 12 or 3  times 4

the numbesr are 4 times 3 so

x^2+7x+12
facotrs out to
(x+4)(x+3) so
x^2+7x+12=0
(x+4)(x+3)=0
set each to zero
x+4=0 and x+3=0
x+4=0
subtract 4 form both sides
x=-4

x+3=0
subtract 3 from both sides
x=-3

x=-4 or -3

X² + 7x + 12 = 0
x = -(7) +/- √((7)² - 4(1)(12))
                     2(1)
x = -7 +/- √(49 - 48)
                   2
x = -7 +/- √(1)
              2
x = -7 +/- 1
           2
x = -7 + 1      x = -7 - 1
          2                   2
x = -6            x = -8
       2                   2
x = -3            x = -4

X= 49; x = 4step 1: foilstep 2: equal both to 0step 3: find x individually