The vertex of this parabola is at (2, -4). when the y-value is -3, the x-value is -3. what is the coefficient of the squared term in the parabola's equation?

A parabola is expressed by a quadratic equation that is either facing on the right, left, upward or downward. Since the function given is opening to the left, then the standard form of the parabola equation is (y-k)^2 = -4a ( x-h) where (h,k) represents the coordinates of the vertex and a is the length of the latus rectum. The vertex is at (2,-4). Substituting, (y+4)^2 = -4a (x-2)

We can find a by substituting the other coordinate, (-3,-3). This is equal to 
(-3+4)^2 = -4a (-3-2)
1 = -4a (-5)
4a = 1/5

Hence the formula becomes (y+4)^2 = -1/5 (x-2)

The coefficient of the squared term hence is 5 as we multiply the whole equation by 5 to convert to standard form.

Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” iswhen n=4,we substitute 4 whetever we see n to get,we simplify to obtain,we further simplify to get,therefore the correct answer is c.

Neither is the answer