There is a margin of error on a food survey of 6%. what is the range of the number of students who prefer chicken strips to meatloaf if 65 of 97 students said they prefer chicken strips and there are 1070 students at the school?

a.674 to 706 students
b.647 to 760 students
c.674 to 760 students
d.647 to 706 students

To answer this, we must recall that the range or the confidence interval is calculated as:

CI = X ± MOE

Where:

X = mean sample size

X can be calculated by:

X = (65/97)*1070

X = 717 students

Since MOE is given in percentage, we will use in the formula:

MOE = 717 * 0.06 = 43

For the range or CI:

CI = 717 ± 43

CI = 674, 760

Therefore 674 to 760 students prefer chicken strips over meatloaf. The answer is letter C.

the answer is 510

step-by-step explanation:

15 • 13 = 195

15 • 12 = 180

15 • 5 = 75

12 • 5 = 60

195 + 180 = 375

375 + 75 = 450

450 + 60 = 510

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step-by-step explanation:

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