In a group of 10 people, 60 percent have brown eyes. two people are to be selected at random from the group. what is the probability that neither person selected will have brown eyes?

60% have brown eyesthat means 40% do not have brown eyes
40% of 10 = 0.40(10) = 4so 4 people do not have brown eyes

probability of first pick not having brown eyes : 4/10 reduces to 2/5
probability of 2nd pick not having brown eyes : 3/9 reduces to 1/3

probability of neither person having brown eyes : 2/5 * 1/3 = 2/15 or 0.13 or 13% 

Hey, can you post the problem?