First correct answer gets brainliest

given the function g(x) = 6(4)x, section a is from x = 0 to x = 1 and section b is from x = 2 to x = 3.

part a: find the average rate of change of each section. (4 points)

part b: how many times greater is the average rate of change of section b than section a? explain why one rate of change is greater than the other. (6 points)

explain!

Ok, so you need to do your work for part a.
f(x) = 5^x
f(x) = 5^0 = 0
f(x) = 5^1 = 5
then you use the formula
f(b) - f(a)/b - a
5 - 0 / 1 - 0 = 5/1 = 5
Then you do the same with 3 and 2
f(x) = 5^2 = 25
f(x) = 5^3 = 125
125 - 25 / 3 - 2 = 100/1 = 100
ok so the average rate of change for each is,
Section A: 5/1 = 5
Section B: 100/1 = 100
This is part A

Ok, so now that we have part A we can see that in Part B it's:
Section B is 20 times greater then A is. This is because Section B is the increasing part of the equation. There for Section B is greater or higher then Section A.

Hope this helps!Ok, so now that we have part A we can see that in Part B it's:
Section B is 20 times greater then A is. This is because Section B is the increasing part of the equation. There for Section B is greater or higher then Section A.

Hope this helps!