Itried to solve this but i keep getting it wrong - can someone !

You got to do SA =2(Pi)r^2 + 2(Pi)rh and substitute. You then simplify everything except Pi.

Hello Gary!

For the bases, upper and lower surface, you have circles with radius = 9 For the side, you have a rectangle in which one side is the height, 20 inches, and the other side is the circumference of the base. Abase = (pi)r^2 Aside = 2(pi)r Remember that these are 2 bases, so Total Area = 2(Abase) + Aside = 2(pi)r^2 + 2(pi)rh = 2(pi)(9^2) + 2(pi)(9)(20) = 162(pi) + 360(pi) = 522(pi) in.^2

The bases are circles, so the areas are easy to see. Think of the lateral (side) area as if you peeled off the label of a can and laid it flat. The shape is a rectangle. The width of that rectangle is the height of the can. The length of the rectangle is wrapped around the can, so it's the circumference of the circle which is the base.

Hope this Helps! Have A Wonderful Day! :)

Idk i am in 5th grade lol