alejandra: 2a2b(β2ab3)β2 = (2a2b)(β2ab3)2
Mathematics, 03.10.2019 12:50 josephraven7942
Who is correct? explain your reasoning.
alejandra: 2a2b(β2ab3)β2 = (2a2b)(β2ab3)2
= (2a2b)(β2)2a2(b3)2
= (2a2b)22a2b6 = 8a4b7
kyle: 2a2b(β2ab3)β2=2a2b(β2)β2a(b3)β2
= 2a2b(4abβ6)
= 2a2bb64a
= ab72
Answers: 1
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Who is correct? explain your reasoning.
alejandra: 2a2b(β2ab3)β2 = (2a2b)(β2ab3)2
alejandra: 2a2b(β2ab3)β2 = (2a2b)(β2ab3)2
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