Since the circumference of the circle can be represented by 2πr, and the area of a parallelogram is determined using a = bh, which represents the approximate area of the parallelogram-like figure?

a) a = (2πr)(r)

b) a = (2πr)(2r)

c)a = (2πr)(r)

d) a = (2πr)(2r)

Check picture 1. divide the circle into n congruent sectors as shown in the picture.

let n be a considerably large number. the larger n, the closer is the length of ab to the length of the arc ab which is 2πr/n

consider the second picture, the sectors are divided in groups of 2, looking in opposite to each other, forming the parallelogram form as shown.

the 2 parallel horizontal bases are each very close to 2πr/2=πr

the other 2 parallel sides, for a very large number n, are almost equal to the height.

so the height is approximately equal to r

area of parallelogram is base*height=πr*r=

answer:

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !