The height of an arrow shot upward can be given by the formula s = v0t - 16t2, where v0 is the initial velocity and t is time. how long does it take for the arrow to reach a height of 48 ft if it has an initial velocity of 96 ft/s? round to the nearest hundredth. the equation that represents the problem is 48 = 96t - 16t2. solve 16t2 - 96t + 48 = 0. complete the square to write 16t² - 96t + 48 = 0 as . solve (t - 3)² = 6. the arrow is at a height of 48 ft after approximately s and after s.

The arrow is at a height of 48 ft after approximately 0.55 seconds and after 5.45 seconds.

Explanation

The given formula is:  

If the initial velocity is 96 ft/s , that means  

For finding the time the arrow takes to reach a height of 48 ft, we will plug into the above formula. So......

So, the arrow is at a height of 48 ft after approximately 0.55 seconds and after 5.45 seconds.

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

answer: the answer is   graph (a)