Abox has 8 beads of the same size, but all are different colors. tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. she repeats this 3 times. what is the probability that tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again?

Step-by-step explanation:

Given: The total number of beads of same size but different color in a box = 8

Since Tamy draws a bead randomly from the box, notes its color, and then puts the bead back in the box. Thus, all the events are independent.

The probability of drawing one bead (any colour) from the box

Also, she repeats this 3 times and all the events are independent of each other.

Therefore, the probability that Tamy would pick a red bead on the first draw, then a white bead, and finally a red bead again =

36 is the final answer! : )

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3