In exponential growth functions, the base of the exponent must be greater than 1. how would the function change if the base of the exponent were 1? how would the function change if the base of the exponent were between 0 and 1?

Step-by-step explanation:

In exponential growth functions, the base of the exponent must be greater than 1.

If base =1 since 1 to power of any natural number is 1, there is no exponential growth or decay.

This becomes a constant function.

If base lies between 0 and 1 we have for values between 0 and 1 raised to powers 2 or 3 will reduce its value.  i.e. there is exponential decay when base of the exponent lies between 0 and 1.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15