An angle measuring (525n)° is in standard position. for which value of n will the terminal side fall below the x-axis? n = 2 n = 3 n = 5 n = 6

An angle is in standard position when its initial ray is in the x-axis, and the angle is formed by rotating the terminal ray counterclockwise, starting from the initial ray.

lets calculate all values of (525n)° for n=2, 3, 5, 6, 

then express these values as 360*k+r, where k is the number of counterclockwise revolutions, and r is smaller than 360

525*2= 1050=360*2+330,

(330° is in the IV.th Quadrant, so below the x axis.)

525*3=1575=360*4+135

(135° is in the II.nd Quadrant, so above the x axis.)

525*5=2625=360*7+105

(105° is in the II.nd Quadrant, so above the x axis.)

525*6=3150=360*8+270

(270° is in the angle between the III.rd and Iv. th Quadrant, so below the x axis.)

n=2, n=6