In a certain clothing store, 6 shirts and 3 ties cost $79.50, and 3 shirts and 2 ties cost $41. determine the cost of each shirt. $10.00 $11.00 $12.00

cost of 1 shirt= $12

Step-by-step explanation:

Let the cost of 1 shirt= $ x

and the cost of 1 tie= $ y.

Now according to the given statements we have:

6 shirts and 3 ties cost $79.50

i.e. 6x+3y= 79.50(1)

Also

3 shirts and 2 ties cost $41

i.e. 3x+2y= 41(2)

Now on solving equation (1) and equation (2) by the method of elimination we will get the value of 'x' and 'y'.

First multiply equation (2) by 2 and subtract (1) by (2) to obtain:

  6x+4y=82

  6x+3y=79.50

  -      -      -

y=2.5

Hence, on putting the value of y in equation (2) we get:

3x+2×(2.5)=41

3x+5=41

3x=41-5

3x=36

x=12 (on dividing both side by 3)

Hence cost of 1 shirt= $12

and cost of 1 tie= $2.5

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92

do you have an easier question cause this shh is hard like theheck

step-by-step explanation: