The length of a rectangle is 3 ft more than twice the width, and the area of the rectangle is 35 ft2 . find the dimensions of the rectangle.

Hello : 
let : y  the length  and : x the  width x< y      x > 0 and y > 0
 y = 3+2x (1)
xy = 35...(2)  
subsct in (2):
x(3+2x) = 35
2x² +3x-35 = 0
delta : (3)² -4(2)(-35) = 289 = 17²
x1 = (-3-17)/4  < 0 ( refused)
x2 = (-3+17)/4 = 7/2
y = 3 +2(7/2) = 10 

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