Mathematics, 14.09.2020 05:01 kkbrookly7496

3x+2y+2z=3
x+2y-+z=5
2x-4y+z=0

Answers: 3

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3x + 2y + 2z = 3 ⇒ 3x + 2y + 2z = 3
1x + 2y - 1z = 5 ⇒ 1x + 2y - 1z = 5
2x - 4y + 1z = 0 4x + 4y + 1z = 8
   4x + 4y + 1z = 8 ⇒ 12x + 12y + 3z = 24
3x + 2y + 2z = 3    3x - 2y = 5 ⇒ 12x - 8y    = 20
1x + 2y - 1z = 5 ⇒ 1x + 2y - 1z = 5     20y + 3z = 4
2x - 4y + 1z = 0 ⇒ 2x - 4y + 1z = 0    20y - 20y + 3z = 4 - 20y
      3x - 2y = 5    3z = 4 - 20y
      3    3
      z = 1¹/₃ - 6²/₃y
         20y + 3(1¹/₃ - 6²/₃y) = 4
      20y + 4 - 20y = 4
      20y - 20y + 4 = 4
   0y + 4 = 4
       - 4 - 4
   0y = 0
      0    0
      y = 0
      20(0) + 3z = 4
      0 + 3z = 4
      3z = 4
   3 3
z = 1¹/₃
      4x + 4(0) + 1¹/₃ = 8
      4x + 0 + 1¹/₃ = 8
      4x + 1¹/₃ = 8
      - 1¹/₃ - 1¹/₃
    4x = 6²/₃      4    4
      x = 1²/₃

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3 is greater then both of those numbers

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2 apples

step-by-step explanation:

taking away equals subtraction. 6-4=2

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3x+2y+2z=3
x+2y-+z=5
2x-4y+z=0...

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