Ngles α and β are angles in standard position such that: α terminates in quadrant iii and sinα = -5/13 β terminates in quadrant ii and tanβ = -8/13 find cos(α - β).

0.5848

Step-by-step explanation:

Sin α=-5/13--> arcsin(-5/13)=α and we know that α is in quadrant III  and because of trigonometry properties we know that sinα can be negative just in quadrant III and IV. There are two options so we choose the option of quadrant III.  α≅202,6°

Tanβ=-8/13---> arctang(-8/13)=β and we know that β is in quadrant II  and because of trigonometry properties we know that tanβ can be negative just in quadrant II and IV. There are two options so we choose the option of quadrant II. β≅148,39°

cos(α-β)=cos(202,6°-148,39)≅0.5848

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

idek

step-by-step explanation: