Removing which point from the coordinate plane would make the graph a function of x?

(-2,1)

Step-by-step explanation:

We know that for the given data points if each x values have a unique y value then only the relation is a function.

If a x value has more than one y values then it will not be a function.

In the given graph, we have below points

(-4,3), (-2,1), (-2,-3), (2,3) and (1,1)

We can see that each x value has a unique y value except -2.

The x value -2 has two y values 1 and -3, which violates the condition of function.

Therefore, if we remove either of these two points then the given relation would be a function.

Hence, we can conclude that on removing (-2,1) would make the graph a function of x.

Second option is correct.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)