1. write a polynomial function of minimum degree with real coefficients whose zeros include those listed. write the polynomial in standard form.
4, -8, and 2 + 5i

f(x) = x4 - 6x3 - 20x2 + 122x - 928

f(x) = x4 - 19x2 + 244x - 928

f(x) = x4 - 6x3 + 20x2 - 122x + 928

f(x) = x4 - 61x2 + 244x - 928

Option 2 -          

Step-by-step explanation:

Given : Zeros of the polynomial 4, -8, and 2 + 5i.

To find : Write a polynomial function of minimum degree with real coefficients whose zeros include those listed ?

Solution :

The zeros of the polynomial are 4, -8, and 2 + 5i.

There is one conjugate exist i.e. 2-5i.

So, The polynomial form of zeros are      

Multiply the factors i.e. first two terms and other two terms multiply each other,

Therefore, Option 2 is correct.                            

f is the midpoint of

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this