Find the approximate solution of this system of equations. y = |x^2 − 3x + 1|
y = x − 1
a) (1,0)
b)(4.5,3.5)
c)(2,1)
d)(3.4,2.3)
e)(0.6,-0.4)

*Hint: When you have two y's, they could equal each other in order to solve for the x value.

|x^2 -3x + 1| = - (x - 1)
x^2 -3x + 1 = -x + 1
x^2 - 2x + 1 = 1
x^2 - 2x = 0
x (x - 2)
x = 2 and x = 0

Once both of them are plugged in, only x = 2 works so that's the value for x. Now we just plug it in order to solve for y.

y = x - 1
y = 2 - 1
y = 1

(2, 1)
The answer would be C.