Write an equation of a line that passes through the point (7, 3) and is parallel to the line y = negative 2 over 3 x + 3. (5 points)

y = 3 over 2 x − 3
y = 3 over 2 x + 3
y = negative 2 over 3 x + 23 over 3
y = negative 2 over 3 x − 23 over 3

m!

i got y-3= -2/3 (x-7)

answer:

step-by-step explanation:

given: equation of line

slope form of the line y=mx+c

comparing with above equation

let the equation of line in form y=mx+a

since the lines are parallel their slopes are equal

therefore,

and this line passes through (7,3) point

so,

putting back in equation of line  

is the required equation.

Y= -2/3x + is -2/ lines will have the same slope.

y = mx + b
slope(m) = -2/3
(7, = 7 and y = 3
now we sub and find b, the y int
3 = -2/3(7) + b
3 = -14/3 + b
3 + 14/3 = b
9/3 + 14/3 = b
23/3 = b

so ur equation is : y = -2/3x + 23/4 < ===

or
u did not even need to put it in point slope form
but since u u do is need to finish and solve for y
y - y1 = m(x - x1)
(7, = 7 and y1 = 3
slope = -2/3
sub
y - 3 = -2/3(x - 7) =
y - 3 = -2/3x + 14/3 =
y = -2/3x + 14/3 + 3 =
y = -2/3x + 14/3 + 9/3 =
y = -2/3x + 23/3 < ==

Letter a i would say