The current size of an image on sandra's computer is shown below:

a rectangle is shown. the length of the rectangle is labeled as length equal to 6 inches and the width is labeled as width equal to 8 inches.

what are the dimensions of the image at fraction 1 over 2 times its current size?

a. length = 4 inches, width = 6 inches
b. length = 3 inches, width = 4 inches
c. length = 8 inches, width = 10 inches
d. length = 12 inches, width = 16 inches

Option B is correct

Length = 3 inches, width = 4 inches

Step-by-step explanation:

As per the statement:

The current size of an image on Sandra's computer is shown below:

A rectangle is shown:

The length of the rectangle is labeled as length equal to 6 inches and the width is labeled as width equal to 8 inches.

⇒Length(l) = 6 inches and width(w) = 8 inches

We have to find the dimension of the image at fraction 1 over 2 times its current size.

Dimensions of the image at

then;

inches

and

inches

Therefore, the dimensions of the image at fraction 1 over 2 times its current size are:

Length = 3 inches, width = 4 inches

attachment?

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it