The hypotenuse of a right triangle is 13 cm. one of the legs is 7 cm longer than the other leg. find the area of the triangle.

Let one side be=x,the longer side =x+7use pythagoras theoremH^2=b^2+h^2169=x^2+(x+7)^2169=2x^2+14x+490=2x^2+14x-1200=(2x-10)(x+12) x=5 or -12,since it is length x=5 the longer side=5+7=12confirmation169=144+25

Iam not sure , but probably 750 or 7.5

It is 6% because if you subtract 69-58=6 so 6% is the answer to your question.