How many values of x must be excluded in the expression x-2/(x+9)(x-5)

We have the expression:( x - 2 ) / ( x + 9 ) ( x - 5 )We have to find how many values of x must be excluded. The rule is : denominator must never equal zero. Anything divided by zero is undefined.x + 9 ≠ 0,  x ≠ - 9x - 5 ≠ 0,   x ≠ 5. Two values must be excluded, x = - 9 and x = 5.

Peanuts r great aren’t they it just has a good taste