Match each linear equation with its slope and a point on the line. tiles slope = 3 point (2, 17) slope = point (19, 2) slope = 3 point (5, 2) slope = point (17, -2) slope = point (-5, 2) pairs equation slope and point y = 3x – 13 arrowboth y = 3x + 11 arrowboth 3y = x +11 arrowboth 3y = x – 13 arrowboth

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

312312

step-by-step explanation: