Anyone
two standard number cubes are thrown, one after the other. what is the probability that the first cube lands showing a 4 or greater and the second cube lands showing a 4 or smaller?
a 0.167
b 0.333
c 0.444
d 1.167

B

Step-by-step explanation:

4 or greater: 1/2 (4,5,6)

4 or smaller: 2/3 (1,2,3,4)

1/2 * 2/3 = 2/6

2/6 = 1/3

1/3 = 0.333

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.