What is the additive inverse of the complex number 13 – 2i?

-13+2i

Explanation:

We have been given with the a complex number 13-2i

The additive inverse of complex number is -(a+ib)

Complex number general representation is a+ib where a and b are real numbers.

Here we have a complex number 13-2i  so a=13 and b=-2i

So, additive inverse will be -(13-2i) after simplifying we will get -13+2i

Therefore additive inverse of complex number is -13+2i

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13